RAS Thermal
Calculation aid

Thermocouple wire resistance per metre

Estimate conductor resistance at any diameter from three verified Type K set points, and check the total against a planned cable run.

Verified set points: φ0.025 mm ≈ 1,900 Ω/m · φ0.5 mm ≈ 5 Ω/m · φ1.0 mm ≈ 1.2 Ω/m. Other diameters are scaled from these by the inverse-square relationship.

Result

Resistance per metre

-Ω/m

Two-wire loop total

-Ω

Gauge Ω/m (est.) 20 m loop
0.25mm 20.0 800
0.5mm 5.00 200
0.8mm 1.95 78.1
1.0mm 1.25 50.0
1.5mm 0.56 22.2
2.0mm 0.31 12.5
3.0mm 0.14 5.6

The table shows the two-wire total for a 20 m one-way run. Where the figure climbs into the thousands of ohms, the run is the problem rather than the sensor, use heavier gauge or extension-grade cable. Scaling from the inverse-square relationship lands within roughly 5% of our measured set points, so treat these as estimates for sizing rather than certificate values.

Frequently Asked Questions (FAQ)

Where do the resistance figures come from?

Three verified Type K set points: φ0.025 mm at roughly 1,900 Ω/m, φ0.5 mm at about 5 Ω/m, and φ1.0 mm at about 1.2 Ω/m. Those three are consistent with a conductor resistance that scales inversely with the square of the diameter, the relationship the tool uses to reach any other gauge, including the φ0.5 mm anchor it is scaled from.

How close is the estimate to the measured figure?

Within a few per cent, and the tool says so rather than implying more. Run the inverse-square relationship back against the three set points and it returns 1.25 Ω/m where φ1.0 mm measures about 1.2 Ω/m, and about 2,000 Ω/m where φ0.025 mm measures about 1,900 Ω/m, a spread of roughly 4 to 5 per cent. Treat the output as an estimate for sizing and comparison, not as a certificate value.

Why does resistance matter to a millivolt signal?

Because a thermocouple generates millivolts, not volts. A long run of fine wire adds series resistance that attenuates the signal before the instrument sees it, a φ0.025 mm Type K conductor at around 1,900 Ω/m is the extreme case. That is why runs longer than about 10 m should use φ0.5 mm or larger, or switch to extension-grade compensating cable.

Is the loop resistance just double the run length?

For a two-wire thermocouple circuit, yes, the current has to travel out and back, so both legs contribute. The tool multiplies by two for that reason. Instruments also have an input resistance limit, and the total loop figure is what has to stay inside it.

Does temperature change the resistance?

It does. Conductor resistance rises with temperature, so a hot run is a little more resistive than the same wire cold. For checking a run against an instrument's input limit the cold figure is the practical one to start from; where a loop runs very hot over a long distance, treat the estimate as the optimistic end of the range.

Run length getting long?

Tell us the distance and the instrument, we supply heavier gauge or extension-grade conductors where fine wire would attenuate the signal.

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